Question

The point (3,b) lies on the circle with radius 6 and center (-1, -2). What are the possible values of b?

Answer 1

Answer:

b = -2 +- sqrt(20)

Step-by-step explanation:

(x – h)2 + (y – v)2 = r2 is the equation you would most likely need.

(x + 1)^2 + (y + 2)^2 = 6^2

(3 + 1)^2 + (b + 2)^2 = 6^2

16 + (b + 2)^2 = 36

(b + 2)^2 = 20

b + 2 = sqrt(20)

b = -2 +- sqrt(20)

Hope this helps!