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If an object were to fall from a
height of 90,000 feet in the air, and
the equation for height as a
function of time is:
y = -16t2 + 90,000
where t is time in seconds and y is height
in feet, how many seconds will it take for
the object to hit the ground?
Set the equation equal to zero and solve.
t = [ ? ] seconds

Respuesta :

We want to determine when it's height is equal to zero:

Set y=0

[tex] - 16t {}^{2} + 90000 = 0[/tex]

[tex] - 16t {}^{2} = - 90000[/tex]

[tex]16t {}^{2} = 90000[/tex]

[tex]t {}^{2} = \frac{90000}{16} [/tex]

[tex]t {}^{2} = 5625[/tex]

[tex]t = \sqrt{5625} = + \: or \: - \: 75 \: seconds[/tex]

[tex]t = 75 \: seconds[/tex]

The negative time is rejected. As we cannot have a negative value.

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