[tex]\sqrt[2]{80x^{2}y^{25} }[/tex]

Answer:
4xy^5√5
Step-by-step explanation:
√80 x √x² x √y^25
=4√5 x x x y^5
= 4√5xy^5
Answer:
4xy^12√(5y)
Step-by-step explanation:
Squares under the radical can be factored out.
[tex]\displaystyle \sqrt{80x^2y^{25}}=\sqrt{(4xy^{12})^2\cdot5y}=\boxed{4xy^{12}\sqrt{5y}}[/tex]
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Additional comment
Some versions of this question may have different exponents.