Question

Two identical spheres, A and B, carry charges of
+6 microcoulombs and -2 microcoulombs,
respectively. If these spheres touch, what will be
the resulting charge on sphere A?

Answer 1

The resulting charge in sphere A from the two given different charges is determined as +2 μC.

Resulting of the two speheres

The resulting charge of the two spheres is determined by suming the two individual charges together as shown below;

Resulting charge = +6 μC - 2 μC

Resulting charge = +4 μC

Charge in sphere A

The resulting charge will be distributed uniformly between the two spheres and charge in sphere A and B will be equal.

Charge in sphere A = charge in sphere B = ¹/₂ x +4 μC = + 2 μC

Thus, the resulting charge in sphere A from the two given different charges is determined as +2 μC.

Learn more about resulting charges here: https://brainly.com/question/26066730