Question

A garbage can of mass 12 kg standing on horizontal ground is pushed by a horizontal force of 40N. If the coefficient of static friction is 0. 32 and the coefficient of dynamic or

kinetic friction is 0. 24 between the can and ground, the acceleration of the garbage can is

____ m/s2

Answer 1

The acceleration of the garbage can is 2.55 m/s².

What is acceleration?

Acceleration is the rate of change of velocity with respect to time.

To calculate the acceleration of the can, we use the formula below

Formula:

• ma = F-mg(η-μ)............ Equation 1

Where:

• F = Horizontal force
• m = mass of the can
• g = acceleration due to gravity
• a = acceleration of the can
• μ = Coefficient of static friction
• η = Coefficient of kinetic friction

Make a the subject of the equation

• a = [F-mg(η-μ)]/m.................. Equation 2

From the question,

Given:

• F = 40 N
• m = 12 kg
• g = 9.8 m/s²
• μ = 0.32
• η = 0.24

Substitute these values into equation 2

• a = [40-12×9.8(0.32-0.24)]/12
• a = (40-9.408)/12
• a = 30.592/12
• a = 2.55 m/s²

Hence, the acceleration of the garbage can is 2.55 m/s².

Learn more about acceleration here: https://brainly.com/question/605631