Question

Suppose that you have a computer with a memory unit of 24 bits per word. In this computer, the assembly program’s instruction set consists of 198 different operations. All instructions have an operation code part (opcode) and an address part (allowing for only one address). Each instruction is storeSuppose that you have a computer with a memory unit of 24 bits per word. In this
computer, the assembly program’s instruction set consists of 198 different operations.
All instructions have an operation code part (opcode) and an address part (allowing for
only one address). Each instruction is stored in one word of memory.
d in one word of memory.

Answer 1

The number of bits that are needed for this operation code (opcode) is 8 bits.

Given the following data:

• Number of operations = 198.

• Instruction size, I = 24 bits.

What is binary encoding?

Binary encoding can be defined as a standard technique that is designed and developed for converting data that are stored in plain text (source alphabets) to a form that is easily read or used by different operating systems (OS), especially through the use of a binary digit (bit) or two-symbol system.

How to calculate the number of bits.

The number of bits that are needed for this operation code (opcode) is given by this mathematical expression:

$2^n > 198\\\\2^8 > 198\\\\256 > 198$

n = 8 bits.

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