Question

if an arrow is aimed at 45.0 angle and needs to land 90.4 m away how fast should it be fired?

Answer 1

Answer:

Explanation:

Range R= u2 sin( 2 theta )/gFor Theta = 45 ,( Range R = 90.4 m given )R = u2/gu2 =Rgu = √Rg= √( 90.4* g)plug in g and get u ( m/s)