Question

Suppose a certain cell reproduces itself in four hours. If a lab researcher begins with 50 cells, how many cells will there be after one day, two days, and three days? (Hint: Use the exponential function y = 50(2x). )

Answer 1

By working with the exponential function, we will see that:

• After 1 day there are 3,200 cells.
• After 2 days there are 204,800 cells.
• After 3 days there are 13,107,200 cells.

How to find the population of the cell?

We know that the population of the cell doubles every four hours, then we can write:

y = 50*(2)^x

Where x is time in lapses of 4 hours, and 50 is the initial population of the cell.

In one day, there are 6 groups of 4 hours, then after one day we have:

• y = 50*(2)^6 = 3,200 cells.

In two days, there are 12 groups of 4 hours, then after two days we have:

• y = 50*(2)^12 = 204,800 cells.

In 3 days, there are 18 groups of 4 hours, then after 3 days there are:

• y = 50*(2)^18 = 13,107,200 cells.

If you want to learn more about exponential functions, you can read:

https://brainly.com/question/11464095