Question

A certain space heater that is connected across 220 V and dissipates 1477 W of power in the form of electromagnetic radiation. What is the resistance of the heater?

Answer 1

Hi there!

We can use the power equation:
$P = \frac{V^2}{R}$

P = Power (W)
V = Potential Difference (V)
R = Resistance (Ω)

Rearrange to solve for Resistance:
$R = \frac{V^2}{P} = \frac{220^2}{1477} = \boxed{32.769 \Omega}$