Question

if the zeros of a quadratic function are -4 and 6, what is the equation of the axis of symmetry of F?

Answer 1

Answer: x = 1

Step-by-step explanation:

$\mathrm{The \ quadratic \ equation \ with \ roots \ at \ -4 \ and \ 6 \ is \ given \ by:}\\ \begin{aligned}&y=(x+4)(x-6) \\&y=xx+x\left(-6\right)+4x+4\left(-6\right) \\&y=x^2-2x-24\end{aligned}$

$\mathrm{For \ a \ quadratic \ equation \ in \ standard-form \ y=ax^{2}+b x+c .}\\The axis of symmetry is a vertical line x=\frac{-b}{2 a} . \\ \marthm{Here } \ b & =-2 \quad, \ a=1\end{array}$

$x=\frac{-(-2)}{2 \times 1}=\frac{2}{2}=1 \\\\ \mathrm{Therefore \ x=1 \ is \ the \ equation \ of \ the \ axis \ of \ symmetry \ of \ F}$