The surface area of the cylinderical tunnel needed to purchase the protective coating is 452.16cm².
Your information is incomplete. Therefore, an overview of the surface area of a cylindrical tunnel will be given.
Let's assume that the radius is 4cm and the height is 7cm. The surface area of the tunnel will be:
= πr²h + 2πr²
= (3.14 × 4² × 7) + (2 × 3.14 × 4²)
= 351.68cm + 100.48cm
= 452.16cm²
In conclusion, the surface area is 452.16cm².
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