Using a geometric sequence, it is found that you can complete the mission 5 times before you earn less than 400 points.
A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.
The nth term of a geometric sequence is given by:
[tex]a_n = a_1q^{n-1}[/tex]
In which [tex]a_1[/tex] is the first term.
In this problem, the amount of points after n times is a geometric sequence with [tex]a_1 = 1000, q = 0.8[/tex], hence the equation is:
[tex]a_n = 1000(0.8)^{n-1}[/tex]
You will earn less than 400 points when:
[tex]a_n < 400[/tex]
Hence:
[tex]1000(0.8)^{n-1} < 400[/tex]
[tex](0.8)^{n-1} < 0.4[/tex]
[tex]\frac{0.8^n}{0.8} < 0.4[/tex]
[tex]0.8^n < 0.32[/tex]
[tex]\log{0.8^n} < \log{0.32}[/tex]
[tex]n > \frac{\log{0.32}}{\log{0.8}}[/tex]
[tex]n > 5.1[/tex]
You can complete the mission 5 times before you earn less than 400 points.
More can be learned about geometric sequences at https://brainly.com/question/11847927