Question

A driver of a 1 000 kg jeepney travelling at a speed of 16,7 m/s bound for divisoria applies the car's brakes when he sees a red light along recto avenue. the car's brakes provide a frictional force of 8 000 n. determine the stopping distance of the car.

Answer 1

The stopping Distance of the Car with the given parameters is; 17.43 m

What is the stopping sight distance?

We are given;

mass; m = 1 000 kg

speed; u = 16.7 m/s

Frictional force; F = 8000 N

distance, s  = ?

final velocity = 0 m/s (car stops)

Formula for final velocity is;

v² = u² + 2as

but a = negative (deceleration)

And F = ma

Thus;

a = F/m = 8000/1000

a = 8 m/s²

Thus;

0 = (16.7)² - 2(8)(s)

278.89 = 16s

s  = 17.43 m

Stopping distance = 17.43 m

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