Respuesta :
Answer: True
Step-by-step explanation:
[tex]\tan ^2\left(x\right)\cos ^2\left(x\right)=1-\cos ^2\left(x\right)[/tex]
[tex]\mathrm{Manipulating\:left\:side}[/tex]
[tex]\tan ^2\left(x\right)\cos ^2\left(x\right)[/tex]
[tex]\mathrm{Use \ the \ basic \ trigonometric \ identity \ \:tan\left(x\right)=\frac{sin\left(x\right)}{cos\left(x\right)}}[/tex]
[tex]=\cos ^2\left(x\right)\left(\frac{\sin \left(x\right)}{\cos \left(x\right)}\right)^2[/tex]
[tex]=\frac{\sin ^2\left(x\right)}{\cos ^2\left(x\right)}\cos ^2\left(x\right)[/tex]
[tex]=\frac{\sin ^2\left(x\right)\cos ^2\left(x\right)}{\cos ^2\left(x\right)}[/tex]
[tex]\mathrm{Cancel\:the\:common\:factor:}\:\cos ^2\left(x\right)[/tex]
[tex]=\sin ^2\left(x\right)[/tex]
[tex]\mathrm{Use \ the \ Pythagorean \ identity \ \cos ^2\left(x\right)-\sin ^2\left(x\right)=1 \rightarrow \sin ^2\left(x\right)=1-\cos ^2\left(x\right)}}[/tex]
[tex]=1-\cos ^2\left(x\right)[/tex]
[tex]1-\cos ^2\left(x\right) =1-\cos ^2\left(x\right)[/tex]
Left side = right side
Therefore, the identity is true