The mass of nitrogen, N₂ required to react with 5.04 grams of oxygen O₂ is 1.76 grams
Balanced equation
2N₂ + 5O₂ —> 2N₂O₅
Molar mass of N₂ = 2 × 14 = 28 g/mol
Mass of N₂ from the balanced equation = 2 × 28 = 56 g
Molar mass of O₂ = 2 × 16 = 32 g/mol
Mass of O₂ from the balanced equation = 5 × 32 = 160 g
SUMMARY
From the balanced equation above,
160 g of O₂ reacted with 56 g of N₂
How to determine the mass of N₂ required
From the balanced equation above,
160 g of O₂ reacted with 56 g of N₂
Therefore,
5.04 g of O₂ will react with = (5.04 × 56) / 160 = 1.76 g of N₂
Thus, 1.76 g of N₂ is needed for the reaction
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