Question

Find the equation of the straight line passing through the point (0, 5) which is perpendicular to the line y=1/6x+2

Answer 1

Hey there!

Perpendicular lines have slopes that are opposite reciprocals. This means we take a number, flop it over, and change its sign.

In this case, the slope is 1/6.

First, flop it over:

6/1 (or just 6)

Then, change its sign:

-6

Now, the line passes through the point (0, 5)

The reason 5 is highlighted is because it's the y-intercept of 5.

So we have the Slope & the Intercept.

See what I mean? Yeah! We can write the line's equation in Slope-Intercept Form (y=mx+b)

In this formula, m stands for the slope, and b stands for the y-intercept.

In this case, -6 is the slope, and 5 is the y-intercept.

Hence, the equation is

$\boxed{\boxed{\bold{y=-6x+5}}}$

Hope everything is clear.

Let me know if you have any questions!

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