Using it's concept, it is found that there is a 0.3482 = 34.82% probability that a randomly selected student in this class did not earn an A on the final exam and did not earn an A for the entire course.
A probability is given by the number of desired outcomes divided by the number of total outcomes.
In this problem, we have that 13 out of 28 students did not earn an A on the final course, and 21 out of 28 students did not earn an A for the entire course, hence:
[tex]p = \frac{13}{28} \times \frac{21}{28} = 0.3482[/tex]
0.3482 = 34.82% probability that a randomly selected student in this class did not earn an A on the final exam and did not earn an A for the entire course.
More can be learned about probabilities at https://brainly.com/question/14398287
