Question

What volume will 8.47kg of sulfur dioxide gas occupy at a pressure of 89.4kPa and a temperature of 40.0°C? ​

Answer 1

Answer:

$V=3850.1769\;L$

Explanation:

Gas law is the mathematical relationship among pressure,volume, temperature, and the number of moles of a gas. It is the equation of state for an ideal gas. Which is because the state of a gas can be known by it pressure, volume, temperature, and number of moles.
Look below which "R" is a constant

$PV=nRT$

$n=8.47kg\times(\frac{1000g}{1kg})\times(\frac{1mol}{64.066g})$

$n=132.2074\;mol$

$V=\frac{nRT}{P}$

$V=\frac{(132.2074\\;mol\times(8.314\frac{L\cdotkPa}{mol\cdotk)}\times(40+273.15)k}{89.4\;kPa}$

or (3.85 x 10^3 L)

$V=3850.1769\;L$

~Lenvy~