The aliased frequency that is due to small sampling frequency is 675 Hz.
The proposed sampling frequency is 2f = 120
The signal frequency that is given in the question is 60Hz
The sampling frequency is 90Hz
a. Using Nyquist frequency,
fn = 0.5*90Hz = 45Hz
The aliased frequency = |n*fn - fs|
aliased frequency = |n*fn - fs|
We have n >= 1/Fs = 17ms
Then the aliased frequency is = 17 x 45 - 90
= 675 Hz
In order to avoid aliasing the sampling frequency, this has to be at least two times the highest frequency.
Therefore Fs =
2xF = 120Hz
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