If 3.500 moles of water react completely according to the following equation, how much heat must be absorbed in kilojoules? 6CO2+6H2O→C6H12O6+6O2ΔH=2,803 kJ

Respuesta :

The amount of heat absorbed in kilojoules when 3.5 moles of water react is 1635.08 KJ

Balanced equation

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂  ΔH = 2803 KJ

From the balanced equation for above,

6 moles of water reacted to absorb 2803 KJ of heat

How to determine the heat absorbed

From the balanced equation for above,

6 moles of water reacted to absorb 2803 KJ of heat

Therefore,

3.5 moles of water will react to absorb = (3.5 × 2803) / 6 = 1635.08 KJ of heat

Thus, 1635.08 KJ of heat were absorbed by the reaction.

Learn more enthalpy change:

https://brainly.com/question/11967318

ACCESS MORE
EDU ACCESS