Question

consider the following two linear equations 3x+3y=-3 "-3+2y=8"

Answer 1

Answer:

Step-by-step explanation:

3x + 3y = -3 ------------(I)

-3x + 2y = 8 -----------(II)

Add both the equations and x will be cancelled and we can find the value of y

(I)          3x + 3y = -3

(II)       -3x  + 2y = 8     {Now add}

                    5y = 5

                      y = 5/5

y = 1

Now, substitute y = 1 in any of the equations. We are going to substitute in equation (I)

3x + 3*1 = -3

3x + 3 = -3

     3x = -3 - 3

     3x = -6

       x = -6/3

x = -2

The solution of the equation is the point of intersection.

Point of intersection = ( -2, 1)

Answer 2

$- 3 + 2y = 8$

$2y = 8 + 3$

$2y = 11$

$y = \frac{11}{2}$

Substitute y=11/2 in the first eq:

$3x + 3( \frac{11}{2} ) = - 3$

$3x = 3 - \frac{33}{2}$

$3x = \frac{6 - 33}{2}$

$3x = \frac{ - 27}{2}$

$x = \frac{ - 27}{6}$