Question

No links and just the answer and explanation

Answer 1

Answer:

x = 1, x = 6

Step-by-step explanation:

Given equation:

$\dfrac{x+2}{x-4}=\dfrac{2x}{x-3}$

Cross multiply:

$\implies (x+2)(x-3)=2x(x-4)$

Expand brackets:

$\implies x^2-3x+2x-6=2x^2-8x$

$\implies x^2-x-6=2x^2-8x$

Collect and combine like terms:

$\implies 2x^2-x^2-8x+x+6=0$

$\implies x^2-7x+6=0$

Factor:

$\implies (x-6)(x-1)=0$

Therefore,

$(x-6)=0\implies x=6$

$(x-1)=0 \implies x=1$