ccornelius17 ccornelius17

28-03-2022
Mathematics

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The sum of 6 consecutive integers is 519
What is the third number in this sequence?

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isalep93 isalep93

28-03-2022

n= the first integer

n + (n+1) + (n+2) + (n+3) + (n+4) + (n+5) = 519

6n + 15 = 519

6n = 594

n = 99

1st one = 99

so 3rd one = 101

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