Question

The sum of 6 consecutive integers is 519
What is the third number in this sequence?

Answer 1

n= the first integer

n + (n+1) + (n+2) + (n+3) + (n+4) + (n+5) = 519

6n + 15 = 519

6n = 594

n = 99

1st one = 99

so 3rd one = 101