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You would like to purchase the car in 2 years. How much money will you need to invest at a 3.3% interest rate compounded annually in order to have $9500 in 2 years? Use the compound interest formula A = P (1 + i)n. (Round final answer to the nearest cent, but otherwise don’t round any intermediate values)

Respuesta :

Answer:

$ 8902.72

Step-by-step explanation:

We would like to calculate the money which we need to invest at 3.3% rate compounded annually for two years . We know that ,

[tex]\longrightarrow \boldsymbol{ A = P \bigg(1+\dfrac{R}{100}\bigg)^n } [/tex]

where the symbols have their usual meaning . So here ,

  • Amount = $ 9500
  • time = 2 years
  • Rate = 3.3%
  • P = The money we need to invest (?)

[tex]\longrightarrow \$ 9500 = P \bigg( 1+\dfrac{3.3}{100}\bigg)^2\\ [/tex]

Simplify RHS ,

[tex]\longrightarrow \$ 9500 = P \bigg(\dfrac{100+3.3}{100}\bigg)^2\\[/tex]

Simplify Nr . in RHS ,

[tex]\longrightarrow \$ 9500 =P\bigg(\dfrac{103.3}{100}\bigg)^2\\ [/tex]

Isolate P ,

[tex]\longrightarrow P = \dfrac{ \$9500\times 100\times 100}{103.3\times 103.3}\\[/tex]

Simplify ,

[tex]\longrightarrow \underline{\underline{\boldsymbol{ P = \$ 8902.72 }}}{} [/tex]

And we are done !

[tex]\bold{Formula: A = P(1 + \frac{r}{100})^{(n)}}[/tex]

Where

  • A = Amount
  • P = Principal
  • R = Rate
  • N = time compounded

[tex] \bold{Solution : } \\ \\ \: \: \: \: \tt \: A = 9,500(1+\frac{3.3\%}{100})^{(2)} \\ \: \: \: \: \: \: \tt \: A = 9,500(1+ 0.033)^{(2)} \\ \tt \: A = 9,500(1.033)^{(2)} \: \: \\ \tt \: A = 10,137.34 \qquad \: \: \: [/tex]

therefore,I need $10,137.34 if would like to purchase the car.

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