Respuesta :

Answer:

A) -4

Step-by-step explanation:

Question

[tex]\sf evaluate \ \dfrac{-4+(m+2)}{n} \ \sf when \ m=\dfrac23 \ and \ \sf n=\dfrac13[/tex]

Solution

Substitute the given values of m and n into the original expression:

[tex]\sf \implies \dfrac{-4+(\frac23+2)}{\frac13}[/tex]

Carry out the operation in the brackets first [tex]\sf (\frac23+3)=\frac83[/tex]

[tex]\sf \implies \dfrac{-4+\frac83}{\frac13}[/tex]

Now carry out the operation in the numerator [tex]-4+\frac83=-\frac43[/tex]

[tex]\sf \implies \dfrac{-\frac43}{\frac13}[/tex]

Dividing by a fraction is the same as multiplying by the flipped version of the fraction (flipped = swap the numerator and denominator of the fraction we are dividing by):

[tex]\sf \implies -\dfrac43 \div \dfrac13=-\dfrac43 \times \dfrac31[/tex]

To multiply a fraction, simply multiply the numerators and multiply the denominators:

[tex]\sf \implies -\dfrac43 \times \dfrac31=\dfrac{-4 \times 3}{3 \times 1}=-\dfrac{12}{3}[/tex]

Finally simplify:

[tex]\sf \implies -\dfrac{12}{3}=-4[/tex]

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