Question

Hi ..
I really need help on this one
​

Answer 1

Answer:

LCM of 3 and 2 is 6

so, firstly we had to make the denominator same:-

$\frac{2(2a + 1) + 3(3a - 1)} {6}$

$\frac{4a + 2 + 9a - 3}{6}$

$\frac{13a - 1}{6}$

Step-by-step explanation:

hope this helps you!!!

XxITSCHOCOLOVERxX

Answer 2

The simplified equation of $\frac{2a+1}{3}+\frac{3a-1}{2}$ is $\frac{13a-1}{6}$

How to simplify an equation?

$\frac{2a+1}{3}+\frac{3a-1}{2}$

$\frac{2a+1}{3}+\frac{3a-1}{2} = \frac{2(2a+1)+3(3a-1)}{6}$

open the bracket in the numerator

Therefore,

$\frac{2(2a+1)+3(3a-1)}{6}=\frac{4a+2 + 9a-3}{6}$

combine like terms in the numerator

$\frac{4a+2 + 9a-3}{6}=\frac{4a+9a+2-3}{6}$

Hence,

$\frac{4a+9a+2-3}{6}=\frac{13a-1}{6}$

Therefore, the final equation is as follows

$\frac{2a+1}{3}+\frac{3a-1}{2}=\frac{13a-1}{6}$

learn more on equation here: https://brainly.com/question/24346515

#SPJ5