Answer:
x = - 2, x = - 3, x = [tex]\frac{3}{2}[/tex]
Step-by-step explanation:
to find the zeros equate p(x) to zero , then
(x + 2)(2x² + 3x - 9) = 0 ← factor the quadratic
(x + 2)(x + 3)(2x - 3) = 0
equate each factor to zero and solve for x
x + 2 = 0 ⇒ x = - 2
x + 3 = 0 ⇒ x = - 3
2x - 3 = 0 ⇒ 2x = 3 ⇒ x = [tex]\frac{3}{2}[/tex]
