Look at the photo atttatched

Answer:
A, D, E are equivalent expressions.
Step-by-step explanation:
A)
[tex]\dfrac{2}{3}a+\dfrac{5}{3}b + ( 8 + 4) - 4 =\dfrac{2}{3}a +\dfrac{5}{3}b + 12 - 4\\\\=\dfrac{2}{3}a+\dfrac{5}{3}b + 8\\\\[/tex]
Here, 8+4 = 12 and when we subtract 4 from 12, we get 8.
[tex]D) 6*(\dfrac{2}{3}a+\dfrac{5}{3}b+8)*\dfrac{1}{6}=6*\dfrac{1}{6}(\dfrac{2}{3}a+\dfrac{5}{3}b+8)\\\\\\=\dfrac{2}{3}a+\dfrac{5}{3}b + 8[/tex]
Here, 6 and 1/6 will be cancelled and we get 1.
[tex]E) \dfrac{2}{3}a+\dfrac{5}{3}b+ 0*\dfrac{1}{3}c+8=\dfrac{2}{3}a+\dfrac{5}{3}b+0+8\\\\=\dfrac{2}{3}a+\dfrac{5}{3}b+8[/tex]
0 multiplied by any value is 0. So, term multiplied by 0 = 0