Using the binomial distribution, it is found that there is a 4% probability of Anne winning two matches.
The formula is:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
In this problem:
The probability that he wins two matches is P(X = 2), hence:
[tex]P(X = 2) = C_{2,2}.(0.2)^{2}.(0.8)^{0} = 0.04[/tex]
4% probability of Anne winning two matches.
More can be learned about the binomial distribution at https://brainly.com/question/24863377