Question

A circular ferris wheel that revolves at a constant rate once every 30 seconds. The
radius of the ferris wheel is 10 m. What is the normal force of the ferris wheel on a 10
kg toddler at the very bottom of the ferris wheel?

Answer 1

The normal force of the ferris wheel on a 10kg toddler at the very bottom of the ferris wheel is 102.41 N.

Centripetal force of the Ferris wheel

The normal force of the ferris wheel on a 10kg toddler at the very bottom of the ferris wheel is calculated as follows;

Fn = Fc + mg

Fn = mω²r + mg

where;

• ω is the angular speed = 1 rev/30 s = 2π/30 s = 0.21 rad/s

Fn = 10(0.21²) 10  + 10(9.8)

Fn = 102.41 N

Thus, the normal force of the ferris wheel on a 10kg toddler at the very bottom of the ferris wheel is 102.41 N.

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