Question

14 f ( x ) = √ 7 + x range

Answer 1

$f(x) = \sqrt{7 + x}$

We know that anything underneath a square has to be positive. so accordingly

$7 + x \geqslant 0$

$x \geqslant - 7$

$domain \: - 7 \leqslant x \leqslant \infty$

The answer to any value of x that that you plug, between -7 & ∞ will be between 0 & infinity.

$range \: \: 0 \leqslant f(x) \leqslant \infty$