Question

hi i need help asap

A=
B=

Answer 1

Answer:

$\rightarrow \sf 8\sqrt[3]{2}$

explanation:

$\rightarrow \sf \sqrt[3]{x^{10}}$

insert -2 as x

$\rightarrow \sf \sqrt[3]{(-2)^{10}}$

simplify

$\rightarrow \sf \sqrt[3]{1024}}$

breakdown

$\rightarrow \sf \sqrt[3]{2 * 8^3}}$

final answer

$\rightarrow \sf 8\sqrt[3]{2}$

→ This a = 8 and b = 2

Answer 2

Answer:

$8\sqrt[3]{2}$

Therefore, a = 8 and b = 2

Step-by-step explanation:

Substitute $x=-2$ into the expression:

$\implies \sqrt[3]{(-2)^{10}}$

Apply exponent rule $(-a)^n=a^n$ if n is even:

$\implies \sqrt[3]{2^{10}}$

Apply exponent rule  $a^{b+c}=a^b \cdot a^c$

$\implies \sqrt[3]{2^9\cdot2^1}$

Apply radical rule  $\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}$

$\implies \sqrt[3]{2^9}\sqrt[3]{2}$

Apply radical rule  $\sqrt[n]{a^m} =a^{\frac{m}{n}}$

$\implies 2^{\frac{9}{3}}\sqrt[3]{2}$

Simplify:

$\implies 2^3\sqrt[3]{2}$

$\implies 8\sqrt[3]{2}$

Therefore, a = 8 and b = 2