Answer:
you subtract a constant from your x in the original function you shift the graph in the positive direction by that number of units.
And if you subtract a constant from your y in the original function you move its graph down by that number of units.
Your original function was y=4x. When you solve for the root of the denominator, you find the vertical asymptote. In this case, it is x=0, i.e. the y-axis.
And when x goes to ∞, y=4∞=0 which means your horizontal asymptote is y=0, i.e. the x-axis. Here is the graph:

Now, you can see the transformation of y=4x below. As is evident, it has shifted 4 units to the right and 3 units down with vertical asymptote at x=4 and horizontal asymptote at y=−3.

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Harold Walden
Jan 15, 2018
translation of 4 units right
translation of 3 units down
y=4x−4−3
Explanation:
translation of 4 units right
translation of 3 units down
y=f(x)→y=f(x−4)−3
y=4x−4−3
Step-by-step explanation:
you subtract a constant from your x in the original function you shift the graph in the positive direction by that number of units.
And if you subtract a constant from your y in the original function you move its graph down by that number of units.
Your original function was y=4x. When you solve for the root of the denominator, you find the vertical asymptote. In this case, it is x=0, i.e. the y-axis.
And when x goes to ∞, y=4∞=0 which means your horizontal asymptote is y=0, i.e. the x-axis. Here is the graph:

Now, you can see the transformation of y=4x below. As is evident, it has shifted 4 units to the right and 3 units down with vertical asymptote at x=4 and horizontal asymptote at y=−3.

Answer link

Harold Walden
Jan 15, 2018
translation of 4 units right
translation of 3 units down
y=4x−4−3
Explanation:
translation of 4 units right
translation of 3 units down
y=f(x)→y=f(x−4)−3
y=4x−4−3
translation of 4 units right
translation of 3 units down
y=4x−4−3
Explanation:
translation of 4 units right
translation of 3 units down
y=f(x)→y=f(x−4)−3
y=4x−4−3
I hope it helps :)
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