Answer:
Vertex: (-1,7)
Equation of the axis of symmetry: x = -1
y-intercept: (0, 5)
Step-by-step explanation:
I will assume that the function is quadratic where it is supposed to be y = -2x² - 4x + 5.
The standard form of quadratic functions can be written as
y = ax² + bx + c
To find the vertex of this function, we need the axis of symmetry (aos).
aos = - b/2a
= - ( -4/-4)
= - 1
Axis of symmetry: x = -1
For the vertex, simply plug in the aos into the function.
f(x) = -2x² - 4x + 5
f(-1) = -2(-1)² -4(-1) + 5
= -2 + 4 + 5
= 7
Vertex: (-1, 7)
Now the y-intercept is the easiest part, since the function is written in standard form. When it is, the y-intercept is always (0, c), which in this case is (0, 5).
y-intercept: (0,5)
