Question

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If y varies jointly as x and z when x = 5, y = 80, and z = 8, what is y when x = 16 and z = 2?
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Answer 1

Hey there!

Let's make an equation

⇒y = (a)(x)(z)

• y = 80
• x = 5
• z = 8

⇒ 80 = a(5)(8)

⇒ 80 = a(40)

⇒ 80 = 40a

Divide both sides by 40

⇒40a/40 = 80/40

⇒a = 80/40

Therefore, a = 2

Let's substitute into first equation

⇒y = (2)(16)(2)

y = 64

So, y = 64

please mark me brainiest, hope this helps