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[tex]\qquad\qquad\huge\underline{\boxed{\sf Answer}}[/tex]

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[tex]\qquad \sf  \dashrightarrow \: {x}^{2} + 4x - 77[/tex]

[tex]\qquad \sf  \dashrightarrow \: {x}^{2} + 11x - 7x - 77[/tex]

[tex]\qquad \sf  \dashrightarrow \: {x}^{} (x + 11) -7(x + 11)[/tex]

[tex]\qquad \sf  \dashrightarrow \: {}^{} (x + 11)(x - 7)[/tex]

Answer:

x = 7

x = -11

Step-by-step explanation:

x² + 4x = 77​

Complete the square to make it a square of a binomial

x² + 4x + 4 = 77 + 4

(x+2)² = 81

Square root both sides (two solutions)

x + 2 = 9

x = 7

x + 2 = -9

x = -11

Hope this helps :)

Have a nice day!

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