Respuesta :
Let that be x
[tex]\\ \rm\rightarrowtail tan\theta=\dfrac{Perpendicular}{Base}[/tex]
[tex]\\ \rm\rightarrowtail tan20=\dfrac{x}{10}[/tex]
[tex]\\ \rm\rightarrowtail 0.364=\dfrac{x}{10}[/tex]
[tex]\\ \rm\rightarrowtail x=10(0.364)[/tex]
[tex]\\ \rm\rightarrowtail x=3.64mi[/tex]

Answer:
[tex]\displaystyle 4\:mi.[/tex]
Step-by-step explanation:
[tex]\displaystyle \frac{10}{h} = cot\:20 \hookrightarrow 10 = hcot\:20 \hookrightarrow \frac{10}{cot\:20} = h; 3,6397023427... \\ \\ \boxed{4 \approx h}[/tex]
OR
[tex]\displaystyle \frac{h}{10} = tan\:20 \hookrightarrow 10tan\:20 = h; 3,6397023427... \\ \\ \boxed{4 \approx h}[/tex]
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