The mass, in grams, of lead that will be produced from the illustrated reaction would be 71.47 grams
Stoichiometric reactions
From the balanced equation of the reaction:
Pb(NO3)2 + 2NaCl ---> PbCl2 + 2NaNo3
Mole ratio of Pb(NO3)2 and NaCl = 1:2
Mole of 15.3 g NaCl = 15.3/58.4
= 0.257 moles
Mole of 60.8 g PbCl(NO3)2 = 60.8/331.2
= 0.184 moles
Thus, NaCl is limiting.
Mole ratio of NaCl to PbCl2 = 1:1
Mas of 0.257 moles PbCl2 = 0.257 x 278.1
= 71.47 grams
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