Question

Bumper car A (296 kg) moving +3.74 m/s makes an
elastic collision with bumper car B (222 kg) moving
+1.85 m/s. What is the velocity of car A after the
collision?

Answer 1

For a bumper car A (296 kg) moving +3.74 m/s, and a bumper car B (222 kg) moving +1.85 m/s, the velocity of car A after the collision is mathematically given as

V1=4.977m/s

What is the velocity of car A after the collision?

Generally, the equation for the Velocity of car A  is mathematically given as

$V1=\frac{m1-m2v1}{m1+m2}v1 +\frac{2m_2}{m1+m2}v2$

Therefore

$V1=\frac{296-222}{296+222}*23.74+\frac{2*222}{296+222}*1.85$

V1=4.977m/s

In conclusion, The velocity of car A after the collision

V1=4.977m/s

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Answer 2

Answer:3.74

Explanation:

it was given same goes for bumper car b