Question

1. A group of 34 women sells at least one of the following foodstuffs: yam, maize and plantain. Of those, 22 sell yam, 14 sell maize, 18 sell plantain, 7 sell both yam and maize, 9 sell yam and plantain and no one sells all three items.

i. Draw a Venn diagram to illustrate this information

ii. Find the number who sell maize aiind plantain

iii. What is the probability that a woman selected at random from the group sells plantain only?

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Answer 1

Answer:

Please see Explanation

Step-by-step explanation:

$a)\ As\ shown\ in\ the\ figure.$

$b)\ According\ the\ picutre,$

$we\ know\ only\ 3\ people$

$sell\ maize\ and\ 5\ people\ sell\ plantain.$

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Answer 2

The 3 people sell only maize, 5 people sell only plantain and 4 people sell maize and plantain and the probability that a woman selected at random from the group sells plantain only is 0.147.

It is given that a group of 34 women sells at least one of the following foodstuffs: yam, maize, and plantain.

22 sell yam, 14 sell maize, 18 sell plantain, 7 sell both yam and maize, 9 sell yam and plantain, and no one sells all three items

What is the Venn diagram?

It is defined as the diagram that shows a logical relation between sets.

The Venn diagram consists of circles to show the logical relation.

i) Venn diagram is shown in the picture below:

ii) As per the picture 3 people sell only maize, 5 people sell only plantain        

   and 4 people sell maize and plantain.

iii)  Total number of women in the group = 34

     The number of women who sells plantain = 5  

We know the probability = $\rm \frac{favorable \ event}{total \ outcome}$

Probability $=\frac{5}{34} \\\\\\= 0.147$

Thus, the 3 people sell only maize, 5 people sell only plantain      

and 4 people sell maize and plantain and the probability that a woman selected at random from the group sells plantain only is 0.147.

Learn more about the Venn diagram here:

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