Question

Three positive integers a, b, and x form an O'Hara triple (a,b,x) if and only if √a+√b=x. For example, (1,4,3) is an O'Hara triple because √1+√4=3. If (36,25,x) is an O'Hara triple, determine the value of x.

Answer 1

Answer:  x = 11

Work Shown:

$\sqrt{a} + \sqrt{b} = x\\\\\sqrt{36} + \sqrt{25} = x\\\\6+5 = x\\\\11 = x\\\\x = 11$

Answer 2

The required value in (36,25,x) is an O'Hara triple, of x is 11.

Three positive integers a, b, and x form an O'Hara triple (a,b,x) if and only if √a+√b=x. For example, (1,4,3) is an O'Hara triple because √1+√4=3. If (36,25,x) is an O'Hara triple,  To determine the value of x.

What is arithmetic?

In mathematics, it deals with numbers of operations according to the statements.

From example,
(1,4,3) is an O'Hara triple because √1+√4=3, in the example sum of the square roots of the first two numbers is equal to the third number. so the value of x in  (36,25,x)  can be determined in the same manner.

Following the example,
√36+√25=x
6 + 5 = x
x = 11

Thus, the required value in (36,25,x) is an O'Hara triple, of x is 11.

Learn more about arithmetic here:

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