Answer:
[tex](3;-2)[/tex]
Step-by-step explanation:
Let's add together the two equations
[tex]I + II : x-8y +9x +8y = 19+11 \rightarrow 10x=30 \rightarrow x =3[/tex]
At this point I would recommend simply using the value of x in the firs equation to find y. [tex]3-8y=19 \rightarrow -8y=16 \rightarrow y=-2[/tex]
Or just multiply the first by 9 and subtract the second.
[tex]9\times I-II: 9x-72y-9x-8y=171-11 \rightarrow -80y=160 y=-2[/tex]