The path difference if the distance between slits on a diffraction grating is 0.60 mm, and one of the angles of diffraction is 0.30° is 1.57 × 10⁻⁶ m.
When the maxima of two waves add up (the two waves are in phase), the amplitude of the resultant wave equals the total of the separate amplitudes, this is known as constructive interference.
We know that for constructive interference, therefore, the formation of bright fringe through a diffraction grating is given by:
d sin θ = n λ
where d is the distance between slits, θ is the angle of diffraction, n is the order of fringe, and λ is the path difference.
As it is given that the distance between slits on a diffraction grating is 0.60 mm, and one of the angles of diffraction is 0.30°, therefore, the path difference can be written as,
[tex]\begin{aligned}\lambda &= \dfrac{(d sin \theta)}{ n} \\\\&=\dfrac{0.60 \times 10^{-3 }m) \times sin (0.30)}{2}\\\\ &= 1.57 \times 10^{-6}\rm\ m\end{aligned}[/tex]
Hence, the path difference is 1.57 × 10⁻⁶ m.
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