Question

After being accelerated to a speed of 1.17×105 m/s , the particle enters a uniform magnetic field of strength 0.800 T and travels in a circle of radius 35.0 cm (determined by observing where it hits the screen as shown in the figure). The results of this experiment allow one to find m/q .

Find the ratio m/q for this particle.

Express your answer numerically in kilograms per coulomb.

Answer 1

The ratio m/q for this particle is mathematically given as

m/q=2.39*10^{-6}

What is the ratio m/q for this particle?

Question Parameters:

After being accelerated to a speed of 1.17×105 m/s

the uniform magnetic field of strength 0.800 T and travels in a circle of radius 35.0 cm

Generally, the equation for the Centrifugal force  is mathematically given as

$qvB=\frac{mv^2}{r}$

Therefore

m/q=(0.8*0.35)/(1.17*10^{5})

m/q=2.39*10^{-6}

In conclusion, the ratio m/q for this particle

m/q=2.39*10^{-6}

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