The total volume of the silo is 116.6 m³.
It is a solid where a hemisphere is kept on top of a cylinder sharing common circular bases.
Diameter of the cylinder of the silo= 4.4m
So, the radius r of the cylinder will be = 2.2m
The radius r of hemisphere = 2.2m (same as cylinder due to common circular bases)
Height h of the cylinder = 6.2m
The total volume of the silo will be the combined volume of the cylinder and hemisphere.
The volume of cylinder = [tex]\pi r^{2} h[/tex]
The volume of hemisphere = [tex]\frac{2}{3} \pi r^{3}[/tex]
Total volume = [tex]\pi r^{2} h+ \frac{2}{3} \pi r^{3}[/tex]
total volume = [tex]\pi r^{2} (h+\frac{2}{3} r)[/tex]
Total volume = [tex]\pi *2.2^{2} (6.2+\frac{2}{3} *2.2)[/tex]
Total volume = 116.6 m³.
Therefore, the total volume of the silo is 116.6 m³.
To get more about solids visit:
https://brainly.com/question/6776134