good evening! Can someone please answer this, ill give you brainliest and your earning 50 points. Would be very appreciated.

[tex]\\ \rm\longmapsto f(x)=40(0.6)^x[/tex]
Now
[tex]\\ \rm\longmapsto f(4)[/tex]
[tex]\\ \rm\longmapsto 40(0.6)^4[/tex]
[tex]\\ \rm\longmapsto 40(1.3)[/tex]
[tex]\\ \rm\longmapsto 5.2ft[/tex]
Option A
Answer:
5.2 ft (nearest tenth)
Step-by-step explanation:
Given function: [tex]f(x)=40(0.6)^x[/tex]
where:
To determine the height of the 4th bounce, substitute [tex]x=4[/tex] into the function:
[tex]\implies f(4)=40(0.6)^4[/tex]
[tex]=40 \cdot 0.1296[/tex]
[tex]=5.184[/tex]
[tex]=5.2 \textsf{ ft (nearest tenth)}[/tex]