Question

2) 13x -11y = -12
4) x - 3y = 6
6) 4x - y = 1
8) 11x - 8y = -47

can someone write the slope-intercept form of these problems with their work shown, if possible?

Answer 1

Answer:

Step-by-step explanation:

Slope-intercept form: y = mx + b

2) 13x -11y = -12

  -13x          -13x

  -11y = -13x - 12

  /-11        /-11

   y = $\frac{13}{11}x+\frac{12}{11}$

4) x - 3y = 6

   -x        -x

    -3y = -x + 6

    /-3        /-3

   y = $\frac{1}{3} x-2$

6) 4x - y = 1

  -4x      -4x

    -y = -4x + 1

    /-1        /-1

    y = 4x - 1

8) 11x - 8y = -47

   -11x        -11x

      -8y = -11x - 47

       /-8         /-8

      y = $\frac{11}{8}x +\frac{47}{8}$

Hope this helps!