Question

In a group assignment, students are required to fill 10 beakers with 0.720 m cacl2. if the molar mass of cacl2 is 110.98 g/mol and each beaker must have 250. ml of solution, what mass of cacl2 would be used? use molarity equals startfraction moles of solute over liters of solution endfraction.. 3.13 g 38.5 g 200 g 617 g

Answer 1

200 grams is the required mass of calcium chloride.

What is molarity?

Molarity (M) is define as the no. of moles (n) of solute present in per liter of solution (V) i.e. M = n/V.

Given molarity of CaCl₂ = 0.720 M

Total volume of solution = 10×250 = 2500 mL = 2.5 L

Moles of CaCl₂ = 0.720×2.5 = 1.8 moles

Now we calculate the moles by using the below formula:

n = W/M, where

W = required mass = to find?

M = molar mass of CaCl₂ = 110.98 g/mol

Mass of CaCl₂ = 1.8 × 110.98 = 199.8 = 200g

Hence, option (3) is correct i.e. 200g. is the required mass of CaCl₂.

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Answer 2

Answer:

c

Explanation: