Question

The two thigh bones (femurs), each of cross-sectional area 10 cm² support the upper part of a human body of 40 kg. Estimate the average pressure sustained by the femurs.

Answer 1

Answer:

Explanation:

Pressure = Force / Area

Force is weight of the upper body = mass*gravity

= 40*10 (take g as 10m/s^2)

= 400N

Area of each bone = 10cm^2 and there are two thigh bones

Total area = 10*2

= 20cm^2

= 0.002m^2

Pressure = 400/0.002

= 200000 N/m^2

= 2*10^5 Pa