Question

What is the product? startfraction 4 n over 4 n minus 4 endfraction times startfraction n minus 1 over n 1 endfraction startfraction 4 n over n 1 endfraction startfraction n over n 1 endfraction startfraction 1 over n 1 endfraction startfraction 4 over n 1 endfraction

Answer 1

The product of the two terms $\dfrac{4n}{(4n-4)} \times \dfrac{(n-1)}{(n+1)}$ is $\dfrac{n}{(n+1)}$.

What is a Fraction?

A fraction is a way to describe a part of a whole. such as the fraction 1/4 can be described as 0.25.

The product of the two fractions can be written as,

$\dfrac{4n}{(4n-4)} \times \dfrac{(n-1)}{(n+1)}$

Taking 4 as the common term from both numerator and denominator of the first fraction, therefore,

$\dfrac{4n}{4(n-1)} \times \dfrac{(n-1)}{(n+1)}\\\\=\dfrac{n}{(n-1)} \times \dfrac{(n-1)}{(n+1)}$

Now, cancelling the common factor from the numerator and the denominator, we will get,

$=\dfrac{n}{(n-1)} \times \dfrac{(n-1)}{(n+1)}\\\\\\=\dfrac{n}{(n+1)}$

Hence, the product of the two terms $\dfrac{4n}{(4n-4)} \times \dfrac{(n-1)}{(n+1)}$ is $\dfrac{n}{(n+1)}$.

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Answer 2

Answer:

B) N/N+1 EDGE2022

Step-by-step explanation: